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This article by Stefan Vorkoetter originally appeared in the
April 2002 issue of
QuietFlyer
magazine and is reproduced here with permission.
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Motor Math
Don't
let the word "math" in the title scare you. There won't
be much of it, but I thought it would be worthwhile explaining just
how one can calculate the performance of a motor.
Last month, we looked at propeller basics (I
cleverly left the word "math" out of the title that time), and one of
the things we came up with was the following formula:
power = k rpm3 diameter4
pitch
This
formula expresses the relationship between a propeller's pitch,
diameter, rpm, and other characteristics (represented by fudge factor
k). For an average propeller, k is about 5.3x10-15
if pitch and diameter are in inches, and power is in Watts.
The
power term in the formula is the amount of power needed to
turn the propeller at the specified rpm. In other words, it is
the required propeller input power. Since the propeller is
attached to the motor shaft (we'll only consider direct-drive
for now), the propeller's input power must equal the motor's
output power.
The Ideal Motor
If
there were such a thing as a perfect 100% efficient motor, then the
motor's output power would be equal to the motor's input
power. In other words, all the Watts flowing into the motor would
make it to the propeller, and hence become the propeller's
input power.
In
reality, there are many losses built into a motor. Some of these are
electrical losses, such as the resistance of the windings and
brushes. Some are magnetic losses, such as the armature's
resistance to being magnetized by current flowing through the
windings. There are also mechanical losses, such as brush and bearing
friction, and drag as the armature rotates through the air inside the
motor.
The Real Motor
For
the purpose of predicting motor performance, a real motor can be
treated as if it consisted of three components: an ideal motor, a
resistor, and a current sink. The sketch below illustrates this. Note that
this is not really what's inside a motor, but rather is
just a circuit that approximates the characteristics of a motor.
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Mathematically, we model a real motor as containing an ideal motor, a resistor, and a current sink.
Click to enlarge.
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The
ideal motor has only one characteristic, and that is the rpm it
produces per Volt of input. This is universally known by the symbol
Kv, and is expressed in rpm/Volt. (Actually, there is a second
characteristic, Kt, which is the amount of torque the motor produces
per Amp of input, but this is always inversely related to Kv, so if
you know Kv, you can compute Kt and vice versa. The equation relating
these two is Kv Kt = 1355 when Kt is expressed in inch-ounces per
Amp).
The
resistor also has one characteristic, its resistance, measured in
Ohms. The resistor represents the winding resistance of the real
motor, which is known by the symbol Ra (the "a" stands
for armature). The resistance serves no useful purpose, but is an
unavoidable physical attribute of the motor.
Finally,
the current sink draws a fixed amount of current, and throws it away.
The amount of current it draws is the no-load current of the real
motor, which is known by the symbol I0 (I is the universal symbol for
current, and the "0" refers to zero load). This is measured in Amps.
Now
lets see how these all fit together.
First
we need to know the voltage reaching the ideal motor, which we'll
call Vi ("i" for ideal). This equals the voltage at the
real motor terminals (we'll call it V), minus the voltage lost
in the resistor. This in turn is equal to the total current (which
we'll call I) times the value of the resistor. So,
Vi = V - I Ra.
Next
we'll need the current reaching the ideal motor, Ii. The total
current flowing into the real motor is divided between the current
sink and the ideal motor. Since the current sink draws a fixed amount
of current, the current reaching the ideal motor is just,
Ii = I - I0.
Now
that we have the voltage and current flowing into the ideal motor, we
can multiply them together to get the power. Furthermore, since the
ideal motor is 100% efficient, the power flowing into it equals the
power used by the propeller. So,
(V - I Ra) (I - I0) = k rpm3 diameter4
pitch.
Finally,
we need to make use of the motor's Kv value somewhere in our
formulae. The ideal motor spins at an rpm directly proportional to
the voltage it receives (Vi). Therefore,
rpm = (V - I Ra) Kv.
These
last two equations form the basis of any calculations we may wish to
perform for a motor. We have nine variables and two equations, so if
we know the values for any seven of these variables, we can solve for
the other two. Fortunately, we generally know everything except rpm
and I.
An Example
Let's
consider a common example, an Astroflight Cobalt 05 motor, 8x4
propeller, and seven SCR type cells. For this motor, we can look up
the following: Kv=2125, I0=2.5, and Ra=0.045. We'll assume that
under load, seven SCR cells will deliver about 7V. For k,
we'll use the value for an average propeller, which is
5.3x10-15. Our diameter and pitch are 8 and 4
respectively. What we want to find out is the current and the rpm. So
if we plug all the numbers we know into our two equations, we get:
(7 - 0.045 I) (I - 2.5) = 5.3x10-15 rpm3 x
84 x 4
rpm
= (7 - 0.045 I) x 2125
Unfortunately, solving these is non-trivial. The easiest way is with a
mathematical software package such as
Maple, but most of
us don't have such a program. If you're mathematically inclined and very
patient, you can solve them by hand, either symbolically or numerically.
Trial
and error is a viable method too. Simply guess a value for I, and use
the second equation to compute rpm. Then substitute your
guessed I and computed rpm into the first equation and see if
it holds true. For example, if we guess that I is 22 Amps, then the
second equation gives us that rpm is 12771. If we put these
values into the first equation, we get 117.2 = 180.9, which is
clearly not true. So, we'll need to try a different guess for
I. If that makes the first equation worse, then we'll need to
go the other way in guessing I. After repeating this a few times,
we'll find that I is 29.4, and rpm is 12067.
Complications
These
equations are adequate for getting an approximate prediction of motor
performance with a given propeller, but there are a few shortcomings.
In the real world, the voltage V is not known exactly, because it
actually depends on the current I. The higher the current, the lower
the voltage, due to the internal resistance of the cells, and also
the speed control. The principals are still the same, but solving the
equations becomes much more complicated.
Specialized electric flight software packages, such as
MotoCalc or
ElectriCalc take all these factors into account and eliminate
the need for the electric modeler to solve these equations directly.
Conclusion
You
certainly don't need to know all this to successfully fly
electric models, but if you like to experiment with power systems, or
are designing your own models, a basic understanding of the
underlying mathematics can make life a lot easier.
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Last updated Wednesday May 28, 2008.
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E-mail Stefan
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